please solve 140
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please help me eloisa.
I multiplied by the reciprocal
2x^2+5x+3·x^2-3x+2
2x^2-x-3. 2x^2-x-6
Then I factored before I miltiplied .
(2x+3)(x+1) · (x-2)(x-1)
(2x-3)(x+1) (2x+3)(x-2)
I cancelled out the common factors.
(x+1)/(2x-3)
This answer is incorrect.
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